Shexp_process.Infixval (>>=) :
'a Shexp_process__.Process.t ->
('a -> 'b Shexp_process__.Process.t) ->
'b Shexp_process__.Process.tSame as bind
val (>>) :
unit Shexp_process__.Process.t ->
'a Shexp_process__.Process.t ->
'a Shexp_process__.Process.ta >> b is the same as a >>= fun () -> b